x-3/2x+10+2x-12=x^2+3x-18/2x+10

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Solution for x-3/2x+10+2x-12=x^2+3x-18/2x+10 equation:



x-3/2x+10+2x-12=x^2+3x-18/2x+10
We move all terms to the left:
x-3/2x+10+2x-12-(x^2+3x-18/2x+10)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x+10)!=0
x∈R
We add all the numbers together, and all the variables
3x-3/2x-(x^2+3x-18/2x+10)-2=0
We get rid of parentheses
-x^2+3x-3/2x-3x+18/2x-10-2=0
We multiply all the terms by the denominator
-x^2*2x+3x*2x-3x*2x-10*2x-2*2x-3+18=0
We add all the numbers together, and all the variables
-x^2*2x+3x*2x-3x*2x-10*2x-2*2x+15=0
Wy multiply elements
-2x^3+6x^2-6x^2-20x-4x+15=0
We do not support expression: x^3

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